memoize
这是一个记忆化函数,用于缓存函数的返回值。当使用相同的参数再次调用时,它会返回缓存的结果,避免重复计算。
默认使用 JSON.stringify(arguments)
作为缓存的 key。
Added in v0.0.1
Usage
typescript
import { memoize } from 'parsnip-kit'
function expensiveCalculation(a: number, b: number): number {
// Simulate an expensive computation process
console.log('Calculating...')
return a + b
}
const memoizedCalc = memoize(expensiveCalculation)
memoizedCalc(2, 3) // Calculating...,returns 5
memoizedCalc(2, 3) // directly return 5, do not call expensiveCalculation
// Use a custom resolver
const memoizedCalcWithResolver = memoize(
expensiveCalculation,
(a, b) => a + b
)
memoizedCalcWithResolver(2, 3) // Calculating...,returns 5
memoizedCalcWithResolver(4, 1) // directly return 5, do not call expensiveCalculation
const memoizedCalcWithAllArgs = memoize(
expensiveCalculation,
(a, b) => a + b,
[2, 3]
)
// Calculating..., call expensiveCalculation to cache
memoizedCalcWithAllArgs(2, 3)
// directly return 5, do not call expensiveCalculation
API
Type Parameter
Arg | Type | Description |
---|---|---|
T | extends (...args: any[]) => any | 要记忆化的函数类型 |
Arguments
Arg | Type | Optional | Default | Description |
---|---|---|---|---|
func | T | false | undefined | 要记忆化的函数 |
resolver | ( ...args: Parameters<T> ) => any | true | undefined | 用于生成缓存键的函数 |
initCache | Parameters<T> | true | undefined | 初始化缓存时的参数 |
Returns
Type |
---|
( ...args: Parameters<T> ) => ReturnType<T> |